0=6x^2+16x+10

Solution for 0=6x^2+16x+10 equation:

0=6x^2+16x+10

We move all terms to the left:

0-(6x^2+16x+10)=0

We add all the numbers together, and all the variables

-(6x^2+16x+10)=0

We get rid of parentheses

-6x^2-16x-10=0

a = -6; b = -16; c = -10;
Δ = b2-4ac
Δ = -162-4·(-6)·(-10)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4}{2*-6}=\frac{12}{-12}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4}{2*-6}=\frac{20}{-12}
=-1+2/3
$